Using the formula do you sound level and disciples are use the intensity of the sound you're measuring. Set an alarm to normal conversation has an intensity of 3.2×10 to the -6

Respuesta :

Answer:

65.1 decibels

Step-by-step explanation:

Given

[tex]I = 3.2 * 10^{-6}[/tex] --- intensity

Required

Determine the sound level

This is calculated using:

[tex]B = 10\log(\frac{I}{I_o})[/tex]

Where:

[tex]I_o = 1 * 10^{-12}[/tex]

So, we have:

[tex]B = 10\log(\frac{3.2 * 10^{-6}}{1 * 10^{-12}})[/tex]

Apply law of indices

[tex]B = 10\log(\frac{3.2 * 10^{-6+12}}{1})[/tex]

[tex]B = 10\log(3.2 * 10^{6})[/tex]

Using a calculator, we have:

[tex]B = 10*6.51[/tex]

[tex]B = 65.1[/tex]