At 25C and 795 torr, carbon dioxide has a solubility of 0.0356 M in water. What is the solubility at 25 C and 2070 torr? ____ M
I know that at a given temperature, the solubility of a gas in a liquid is directly proportional to its pressure but how would that be set up in an equation..?

Respuesta :

If you want to do real scientifically, the equation is 
p = kc. 
We evaluate k = p/c and plug in the first set of conditions. 
k = 795/0.0356 = 22,331 

Then p = kc and solve for c 
c = p/k = 2070/22,331 = 0.093

The mixing of solute in the solvent is called solubility. In a solution, there are two types of components, these components are solute and solvent.

  • Solute - a component that presents in less amount.
  • Solvent - a component that is present in a large amount.

According to the question, the torr is defined as the torr is a unit of pressure based on an absolute scale, defined as exactly 1/760 of a standard atmosphere.

The equation is  

[tex]p = kc[/tex]  

hence, [tex]k = \frac{795}{0.0356} = 22,331[/tex]

After solving the equation,

[tex]c = \frac{p}{k} \\\\= \frac{2070}{22,331}\\\\ = 0.093\\[/tex]

Hence, the solubility is 0.093.

For more information, refer to the link:-

https://brainly.com/question/11228968