Answer: Hence required probability = 0.004307
Step-by-step explanation:
Given an industrial machine has 0.12 defective rate and to find probability that fewer than 3 defective widgets run of 75 items,
⇒[tex]P(x < 3)=P(x=2)+P(x=1)+P(x=0)[/tex], since P(x=r)=[tex]_nc_r P^rq^n^-^r[/tex]
Here P=0.12, q=1-p, 1-0.12=0.88, n=75
the rest of the answer is explained in the photo below.
