Respuesta :

Answer:

  C)  4.65 mA

Explanation:

The series circuit will have a voltage drop of about 0.7 V across the silicon diode, so the voltage drop across the 2 kΩ resistor is 10 -0.7 = 9.3 V. The current through the resistor is given by Ohm's Law:

  I = V/R = 9.3 V/(2 kΩ)

  I = 4.65 mA