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If a system does 63.0 kJ of work on its surroundings and releases 105 kJ of heat, what is the change in the internal energy of the system, in kJ

Respuesta :

Answer:

-42 kJ

Explanation:

Q = ΔE + W

W = -63.0 kJ

Q = -105 J

so -105 = ΔE + (-63)

ΔE = 63 - 105 = -42 kJ

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