grecon882
contestada

PLS HELP In circle A, secant EC and tangent BC intersect at point C. mЕВ = 171° and mBD 83°. What is mBCD?

Enter your answer in the box.​

PLS HELP In circle A secant EC and tangent BC intersect at point C mЕВ 171 and mBD 83 What is mBCD Enter your answer in the box class=

Respuesta :

Answer:

∠ BCD = 44°

Step-by-step explanation:

the secant- tangent angle BCD is half the difference of the intercepted arcs, so

∠ BCD = [tex]\frac{1}{2}[/tex] (EB - BD) = [tex]\frac{1}{2}[/tex] (171 - 83)° = [tex]\frac{1}{2}[/tex] × 88° = 44°

Otras preguntas