Answer:
[tex]x=1~ \text{and}~ x = -6~ \text{but}~ -6 ~\text{is extraneous.}[/tex]
Step by step explanation:
[tex]2-x = 3-\sqrt{7-3x}\\\\\implies \sqrt{7-3x} = 3-2+x\\\\\implies \sqrt{7-3x} = 1+x\\\\\implies 7-3x = (1+x)^2\\\\\implies 7-3x=1+2x+x^2\\\\\implies x^2+3x+2x+1-7=0\\\\\implies x^2+5x -6 =0\\\\\implies x^2+ 6x-x -6=0\\\\\implies x(x+6)-(x+6)=0\\\\\implies (x-1)(x+6)=0\\\\\implies x =1~~, x = -6[/tex]
[tex]x=-6~ \text{Doesn't satisfy the original equation, so it is an extraneous solution.}[/tex]
