Respuesta :

[tex]\dfrac{\sqrt{24}}{8}+\dfrac{\sqrt{54}}{12}=\dfrac{2\sqrt6}{8}+\dfrac{3\sqrt6}{12}=\dfrac{\sqrt6}{4}+\dfrac{\sqrt6}{4}=\dfrac{2\sqrt6}{4}=\dfrac{\sqrt6}{2}[/tex]