Respuesta :

#1

Perpendicular of right angles triangle

  • p²=34²-16²
  • p²=30²
  • p=30

Area of triangle

  • 1/2(30)(16)
  • 15(16)
  • 240units²

Area of rectangle

  • 34(21)
  • 714units²

Area of shaded region

  • 714-240
  • 474units²

#11

Area of shaded region

  • πr²/4
  • π(6)²/4
  • 36π/4
  • 28.3cm²

Answer:

10)  474 units²

11)  28.3 cm²  (nearest tenth)

Step-by-step explanation:

Question 10

To calculate the shaded area, subtract the area of the triangle from the area of the rectangle.

First, find the base of the triangle using Pythagoras' Theorem:

a² + b² = c²

(where a and b are the legs, and c is the hypotenuse of a right triangle)

Given:

  • a = 16
  • c = 34

Substituting the given values into the formula to find the base of the triangle:

⇒ a² + b² = c²

⇒ 16² + b² = 34²

⇒ b² = 34²- 16²

⇒ b² = 900

⇒ b = √(900)

⇒ b = 30

Area of triangle = 1/2 × base × height

                          = 1/2 × 30 × 16

                          = 240 units²

Area of rectangle = width × length

                             = 21 × 34

                             = 714 units²

Shaded area = area of rectangle - area of triangle

                      = 714 - 240

                      = 474 units²

Question 11

The central angle of the shaded area is a right angle = 90°

Angles around a point sum to 360°

[tex]\implies \sf \dfrac{90^{\circ}}{360^{\circ}}=\dfrac{1}{4}[/tex]

Therefore, the shaded area is a quarter of the area of the circle.

[tex]\begin{aligned}\textsf{Area of a circle} & = \sf \pi r^2 \quad \textsf{(where r is the radius)}\\\\\implies \textsf{Shaded Area} & = \sf \dfrac{1}{4}\pi r^2\\\\& = \sf \dfrac{1}{4}\pi (6)^2\\\\& = \sf 9\pi \:\:cm^2\\\\& = \sf 28.3\:\:cm^2\:\:(nearest\:tenth)\end{aligned}[/tex]