The factors of 15 exists -1, 1, -3, 3, -5, 5, -15, 15
The factors of 8 exists -1, 1, -2, 2, -4, 4, -8, 8
Therefore, the correct answer is 5, -1/4, -3, and 5/2.
The theorem notes that each rational solution x = p⁄q, noted in lowest terms so that p and q exist relatively prime, satisfies: p exists an integer factor of the constant term [tex]a_0[/tex], and q exists an integer factor of the leading term.
The possible rational zeros exist in the factors of 15 over (fraction bar) factors of 8.
The factors of 15 exists -1, 1, -3, 3, -5, 5, -15, 15
The factors of 8 exists -1, 1, -2, 2, -4, 4, -8, 8
So the possible rational zeros. I'm just going to put the factors of 15 over the factors of 8 then
-1/-1 = 1
-1/1 = -1
-1/-2 = 1/2
-1/2 = -1/2
-1/-4 = 1/4
-1/4 = -1/4
-1/-8 = 1/8
-1/8 = -1/8
Now I'm going to go to 1 and put it all over the factors of 8.
I can see some of your choices there exists 5/1 = 5, I already listed the -1/4 above, -3/1 = -3, and 5/2.
Therefore, the correct answer is 5, -1/4, -3, and 5/2.
To learn more about rational root theorem refer to:
https://brainly.com/question/25216212
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