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If 30g of HCl is dissolved and 10g of NaCl is produced, what is the theoretical yield of the experiment?

Respuesta :

HCl + NaOH = NaCl + H₂O

m(HCl)=30g
m'(NaCl)=10g
M(HCl)=36.46 g/mol
M(NaCl)=58.44 g/mol

m(NaCl)/M(NaCl)=m(HCl)/M(HCl)

theoretical mass of sodium chloride
m(NaCl)=M(NaCl)m(HCl)/M(HCl)
m(NaCl)=58.44*30/36.46=48.09 g

the practical yield of the reaction
w=m'(NaCl)/m(NaCl)=m'(NaCl)M(HCl)/M(NaCl)m(HCl)

w=10*36.46/(58.44*30)=0.2080 (20.80%)

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