You did not show the cone or give its dimensions, however we can solve for the general case:
V=(hπr^2)/3 This will be our initial volume.
And we are told that the volume leaving the cylinder is:
V=15t
So the remaining liquid at any time t, we have:
V=(hπr^2)/3-15t
All of the fluid will have been removed when V=0 so
(hπr^2)/3-15t=0
(hπr^2)/3=15t now divide both sides by 15
t=(hπr^2)/45 minutes, where h=height of cone, r=radius of cone
And since you are asked to approximate π≈3.14
t=(3.14hr^2)/45, now you just have to plug in the height and radius of the cone to solve for how many minutes it will take for the cone to empty.
