momilaortiz905 momilaortiz905

11-01-2024
Mathematics

contestada

How many liters of a 20% alcohol solution must be mixed with 60 liters of a 70% solution to get a 60% solution?
A) 7.5L
B) 100L
C)1.51L
D) 75 L

Respuesta :

karmenchong karmenchong

11-01-2024

Answer:

15 L

Step-by-step explanation:

Let the volumn of 1st solution = n liters

Total alcohol = Total alcohol

20% × n + 70% × 60 = 60% × (n + 60)

0.2 × n + 42 = 0.6 × n + 36

0.6n - 0.2n = 42 - 36

0.4n = 6

n = 6 ÷ 0.4

= 15 liters

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