The magnitude of his accelerations on the pad is 66.64 m/s²
Further explanation
Acceleration is rate of change of velocity.
[tex]\large {\boxed {a = \frac{v - u}{t} } }[/tex]
[tex]\large {\boxed {d = \frac{v + u}{2}~t } }[/tex]
a = acceleration ( m/s² )
v = final velocity ( m/s )
u = initial velocity ( m/s )
t = time taken ( s )
d = distance ( m )
Let us now tackle the problem!
Given:
height of pole vaulter above the pad = H = 4.2 - 0.8 = 3.4 m
distance of compression of pad = d = 50 cm = 0.5 m
Unknown:
a = ?
Solution:
Firstly , we calculate the velocity of pole-vaulter before hitting the pad.
[tex]v^2 = u^2 + 2gH[/tex]
[tex]v^2 = 0^2 + 2 \times 9.8 \times 3.4[/tex]
[tex]v^2 = 1666/25[/tex]
[tex]v = \frac{7 \sqrt{34}}{5} ~ m/s[/tex]
Next , we can calculate the magnitude of his accelerations on the pad.
[tex]v^2 = u^2 + 2gH[/tex]
[tex]0^2 = 1666/25 + 2 \times a \times 0.5[/tex]
[tex]a = -1666/25[/tex]
[tex]\large {\boxed {a = -66.64 ~ m/s^2} }[/tex]
Learn more
- Velocity of Runner : https://brainly.com/question/3813437
- Kinetic Energy : https://brainly.com/question/692781
- Acceleration : https://brainly.com/question/2283922
- The Speed of Car : https://brainly.com/question/568302
Answer details
Grade: High School
Subject: Physics
Chapter: Kinematics
Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle
