Answer: The correct answer is Option 1.
Explanation:
We are given two intermediate equations and a final net equation for the formation of calcium carbonate. To form a net equation, we have to apply some operations on the second equation.
Two intermediate equations given are:
[tex]Ca(s)+CO_2(g)+\frac{1}{2}O_2(g)\rightarrow CaCO_3(s)[/tex] [tex]\Delta H_1=-812.8kJ[/tex]
[tex]2Ca(s)+O_2(g)\rightarrow 2CaO(s)[/tex] [tex]\Delta H_2=-1269.8kJ[/tex]
To get the final equation, we will half the second equation and reverse the equation, we get:
Equation 1: [tex]Ca(s)+CO_2(g)+\frac{1}{2}O_2(g)\rightarrow CaCO_3(s)[/tex]
Equation 2: [tex]CaO(s)\rightarrow Ca(s)+\frac{1}{2}O_2(g)[/tex]
Net Equation: [tex]CaO(s)+CO_2(g)\rightarrow CaCO_3(s)[/tex]
Hence, the correct answer is Option 1.
