f(x) = 6x^2 + 3x - 6
The derivative, and thus the slope of the T. L. to the graph, is f '(x) = 12x + 3. Set this result = to -3 and solve for x:
12x + 3 = -3 => 12x = - 6 and x = -1/2
6 + 6 - 24
If x = -1/2, y = f(-1/2) = 6(1/4) - 3(-1/2) - 6 = ----------------- = -6
4
The slope of the T. L. to the graph will be -3 at the point (-1/2, -6).
