The ordered pairs will be the points on the parallel line are
(-8, 8) and (2, 2)
(-2, 1) and (3, -2)
What is the slope of a line?
A slope of a line is the change in y coordinate with respect to the change in x coordinate.
How to find the slope of line from the two points?
If [tex](x_{1} ,y_{1} )[/tex] and [tex](x_{2} , y_{2} )[/tex] be the two points then the slope of the line is given by
[tex]slope = \frac{y_{2} -y_{1} }{x_{2}-x_{1} }[/tex]
According to the given question.
We have slope of a line is [tex]\frac{-3}{5}[/tex].
As, we know that the two parallel lines have the same slope.
Now according to the given ordered pairs
A). (-8, 8) and (2, 2)
[tex]slope = \frac{2-8}{2+8} = \frac{-6}{10} =\frac{-3}{5}[/tex]
Therefore, (-8, 8) and (2, 2) are the ordered pairs could be the points on the parallel line.
B) (-5, -1) and (0, 2)
[tex]slope = \frac{2+1}{0+5} =\frac{3}{5} \neq \frac{-3}{5}[/tex]
Hence, the ordered pair (-5, -1) and (0, 2) will never be the points on the parallel line.
C) (-3, 6) and (6, -9)
[tex]slope = \frac{-9-6}{6+3} =\frac{-15}{9} =\frac{-5}{3}\neq \frac{-3}{5}[/tex]
The ordered pair (-3, 6) and (6, -9) will never be the points on the parallel line.
D). (-2, 1) and (3, -2)
[tex]slope = \frac{-2-1}{3+2} =\frac{-3}{5}[/tex]
Therefore, (-2, 1) and (3, -2) are the ordered pairs could be the points on the parallel line.
E). (0, 2) and (5, 5)
[tex]slope = \frac{5-2}{5-0} =\frac{3}{5} \neq \frac{-3}{5}[/tex]
Therefore, (0, 2) and (5, 5) are the ordered pairs could not be the points on the parallel line.
Hence, the ordered pairs will be the points on the parallel line are
(-8, 8) and (2, 2)
(-2, 1) and (3, -2)
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