2H2 + O2 → 2H2O
If 720.8 g of water are produced from the reaction, calculate the following:
moles of H2:
moles of O2:
grams of O2:

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Respuesta :

okay
Mr (H2O)= 18g
therefore moles of H2O
is 720.8/18= 40.04mol
the ratio of H2 to O2 to H2O is
2 : 1 : 2
so moles of H2 is same as H2O here
H2= 40.04moles

moles of O2 is half
so 40.04 x 0.5
20.02moles

grams of O2 is
its moles into Mr of O2
that's 20.02 x 32 = 640.64g