Answer:
Perimeter is 129 inches.
Step-by-step explanation:
We are given,
A quadrilateral with sides lengths [tex](4x^2+8x),(3x^2-5x+20),(7x+30),31[/tex] inches.
Now, the values of the side lengths when x = 2 are,
[tex](4x^2+8x)=(4\times 2^2+8\times 2)=(4\times 4+16)=16+16=32\ inch\\\\(3x^2-5x+20)=(3\times 2^2-5\times 2+20)=(3\times 4-10+20)=12+10=22\ inch\\\\(7x+30)=(7\times 2+30)=14+30=44\ inch[/tex]
Since, Perimeter of a quadrilateral = Sum of its sides.
Then, Perimeter of given quadrilateral = 32 + 22 + 44 + 31 = 129 inches.
Hence, the perimeter is 129 inches.
