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The chemical equation below shows the combustion of propane (C3H8). C3H8 + 5O2 mc012-1.jpg 3CO2 + 4H2O The molar mass of oxygen gas (O2) is 32.00 g/mol. The molar mass of C3H8 is 44.1 g/mol. What mass of O2, in grams, is required to completely react with 0.025 g C3H8? 0.018 0.034 0.045 0.091

Respuesta :

kenmyna
   The  mass  of O2   required  to   completely  react  with  0.025g C3H8  is  calculated  as  follows

C3H8  +  5O2 = 3CO2  +  4H2o

 calculate the moles  of  C3H8   that is moles=mass/molar mass
= 0.025g  /  44.1 g/mol=   5.669  x10^-4  moles

by  use of  mole  ratio from  reacting  equation   between  C3H8  to  O2  which is  1:5 the  moles  of  O2 =  5  x  (5.669  x10^-4)  =  2.83  x10^-3  moles

mass  of  O2  =  moles  x  molar  mass
=  (2.83  x10^-3)moles  x  32 g/mol  =  0.091   g ( answer  D)
amovoce

Answer:

0.091.

Explanation: